Đề song ngữ Vật lí 9 - Đề 2 - Phạm Văn Minh (Có đáp án)

 Đề 2
Ex1: If the segment is like a drawing, where R1 = 4Ω ; R3 
 Rx
= 12Ω and the second circuit voltage is 14V. For the 
 A R1 B
power consumption on all 28w, the value of Rx value is: R3
Ex2: Resistor R1 = 3  , R2 = 6  in series, then connected to the power supply with 
a voltage of 4.5 V. Power consumption on resistor R2 is:
Ex3: A metal conductor of resistor R is cut into two equal segments, and then 
paralleled, the equivalent resistance is 10 Ω. The value of R is
Ex4: Resistor R1 = 4 ; R2 = 6 ; R3 = 12 parallel to each other. The equivalent 
resistance R of the circuit segment is
Ex5: For the circuit as shown: Know R1 = R2 = 12W, R3 
 R1
 R
= 6W. The equivalent resistance of the AB circuit is A 3 B
Ex6: Resistor R1= 10 withstand the maximum voltage 
set at its two ends is U1 = 6V. Resistor R2= 5 R2
withstand the largest voltage set at its two ends is U2 = 
4V. The circuit consisting of R1 and R2 in series with the largest voltage applied at 
both ends of this circuit is:
 Ex7: Ex8: ( chưa học)
 Ex9: Two resistors R1= 30 and R2= 60 in parallel to the voltage U = 120V. The 
 power consumption of the parallel circuit is as follows:
Ex10: Simultaneously parallel two resistors R1= 30 ; R2= 20 to the circuit with a 
voltage of 30V. The current in the main circuit is:
 Answer Ex11 in English
Ex11: For side drawings:Lamp 1: 6V-12W, V
resistance R = 6Ω. Connect the power to the normal 
 R B
2 lights, the voltmeter is only 12V. Calculate power A
 C
on two lights? Đ2
 Đ1 Đáp án
1-6 ; 2 -4 ; 3-40; 4-2; 5-12; 6-9; 7,8 chưa học 9- 720; 10 – 2,5 
11- 18W
 =
Ex9: Two resistors R1= 30 and R2= 60 in parallel to the voltage U = 120V. The 
power consumption of the parallel circuit is as follows:
 Answer:720W
Ex10: Simultaneously parallel two resistors R1= 30 ; R2= 20 to the circuit with a 
voltage of 30V. The current in the main circuit is:
 Answer: 2,5A
Ex11: For side drawings:Lamp 1: 6V-12W, V
resistance R = 6Ω. Connect the power to the normal 
 R B
2 lights, the voltmeter is only 12V. Calculate power A
 C
on two lights? Đ2
 Đ1
Solusion
Because a normal light 1 should:
U1=6v, P1=12W 
=> I1 =2A ; 
 U 6
 I 1 1A
 R R 6 
 I I 1 IR 3A I2 3A
We have U1 +U2=12v => U2 =6v
Calculate power on two lights is: P1=U2I2=6.3= 18W